3x^2-70x+250=0

Solution for 3x^2-70x+250=0 equation:

3x^2-70x+250=0

a = 3; b = -70; c = +250;
Δ = b2-4ac
Δ = -702-4·3·250
Δ = 1900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1900}=\sqrt{100*19}=\sqrt{100}*\sqrt{19}=10\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-10\sqrt{19}}{2*3}=\frac{70-10\sqrt{19}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+10\sqrt{19}}{2*3}=\frac{70+10\sqrt{19}}{6}
$